Exercises
Exercise 1. What is the bond order for C2+?
First draw the MO diagram. There are a total of 11 electrons (subtract one electron for the positive charge).
Bond order = 1/2(bonding – antibonding) = 1/2 (7 – 4) = 1.5
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Exercise 2. What is the bond order for O2–?
Draw the MO diagram. There are a total of 17 electrons.
Bond order = 1/2(bonding – antibonding) = 1/2 (10 – 7) = 1.5
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Exercise 3. Write the MO configuration for N2+. Is this diamagnetic or paramagnetic? What is the bond order?
First we draw the MO diagram.
The electron configuration is (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (π2p)4 (σ2p)1
The ion is paramagnetic due to an unpaired electron.
Bond order = 1/2 (9 – 4) = 2.5
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Exercise 4. What is the MO configuration for C2–? What is the bond order?
First we draw the MO diagram.
Bond order = 1/2 (9 – 4) = 2.5
The electron configuration is (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (π2p)4 (σ2p)1
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Exercise 5. What is the bond order for NO+?
First we draw the MO diagram. Notice in the diagram the energy for the more electronegative atom, O, is lower due to the stabilization of the lone pairs of electrons.
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Exercise 6. Write the electron configuration for CO.
First we draw the MO diagram. Notice in the diagram the energy for the more electronegative atom, O, is lower due to the stabilization of the lone pairs of electrons.
The electron configuration is (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (π2p)4 (σ2p)2