Exercise Solutions Balancing Equations

Exercises

Exercise 1. Balance the following chemical equations.

a) Mg + HNO3 → H2 + Mg(NO3)2

Mg + 2 HNO3 → H2 + Mg(NO3)2

 
b) P4O10 + H2O → H3PO4

P4O10 + 6 H2O → 4 H3PO4

 
c) C6H14 + O2 → CO2 + H2O

For this problem, balance the carbons and hydrogens first.
C6H14 + O26 CO2 + 7 H2O
There are 2 oxygens on the reactant side and 19 oxygens on the product side.
Note, 19/2 O2 atoms = 19 oxygen atoms.
C6H14 + 19/2 O26 CO2 + 7 H2O
Finally, multiply the equation coefficients by 2 to clear the fraction.
2 C6H14 + 19 O212 CO2 + 14 H2O

 
d) CaCN2 + 3 H2O → CaCO3 + NH3

CaCN2 + 3 H2O → CaCO3 + 2 NH3

 
e) SiCl4 + H2O → SiO2 + HCl

SiCl4 + 2 H2O → SiO2 + 4HCl

 
Exercise 2. Ammonia gas and molecular oxygen gas react to produce nitrogen monoxide gas and liquid water.
Write a balanced chemical equation.

4NH3 + 5 O24 NO + 6 H2O

 
Exercise 3. Consider the following chemical equation and interpret it in words (Make sure the equation is balanced).
Fe2O3 (s) + C (s) → Fe (s) + CO2 (g)

The balanced equation is: 2 Fe2O3 (s) + 3 C (s) → 4 Fe (s) + 3 CO2 (g)

There are 2 moles of iron(III) oxide that react with 3 moles of solid carbon to produce 4 moles of solid iron and 3 moles of carbon dioxide gas.

Exercise 4. Element A (red spheres) reacts with Element B (blue spheres). Write a balanced chemical equation for this process.

Molecular representation of a chemical reaction

Count the number of reactant molecules and product molecules. The reactant box contains 9 red molecules, A2 and 3 blue molecules, B2. The product box contains 6 A3B molecules.

The reaction is: 9 A2 + 3 B2 → 6 A3B
We can divide the coefficients in the equation by 3 and our balanced equation is:
3 A2 + B2 → 2 A3B

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