Standard Enthalpies of Formation

A pure substance is the most stable form of the substance at 1 atm and the temperature of interest. In most tables the temperature is 25°C (298 K). The standard state of a substance in aqueous solution, is a concentration of 1.00 M and for a gas the pressure is 1 atm. The standard enthalpy (heat) of reaction is given by ΔHorxn. The nought superscript means standard state.

A formation equation is written for 1 mole of substance formed from its elements. For example the formation of NaCl(s) from its elements is written as:

Na (s) + 1/2 Cl2 (g) → NaCl (s)

If the equation was written as below, it would not be a formation equation because there are two moles of NaCl. Formation equations are always written in terms of 1 mole of product.

2 Na (s) + Cl2 (g) → 2 NaCl (s)    This is not a formation equation.

The standard enthalpy of formation, ΔHof, is the enthalpy change for a formation equation when all substances are in their standard states. The standard enthalpy of formation for the following formation reaction is -411.2 kJ/mol.

Na (s) + 1/2 Cl2 (g) → NaCl (s)     ΔHof = -411.2 kJ/mol

Values of ΔHof can be found in tables or in the CRC Handbook of Chemistry and Physics. Click to see a table of thermodynamic quantities. The ΔHof, values for elements in their most stable state are zero. For our reaction, ΔHof, for both Na (s) and Cl2 are zero as both are elements in their standard states. The value for 1 mole of NaCl is -411.2 kJ/mol.

In this example, we are asked to write a formation equation for liquid ethanol, CH3CH2OH. Recall, the formation equation is for 1 mole of a substance formed from its elements. The elements are C (graphite), H2 (g), and O2 (g)

C (graphite) + H2 (g) + O2 (g) → CH3CH2OH (l)

Next, balance the equation while keeping in mind there can only be 1 mole of ethanol in the balanced formation reaction. The balanced formation equation is:

2 C (graphite) + 3 H2 (g) + 1/2 O2 (g) → CH3CH2OH (l)

Finally, we look up ΔHof for liquid ethanol, and it is -277.7 kJ/mol.

2 C (graphite) + 3 H2 (g) + 1/2 O2 (g) → CH3CH2OH (l)     ΔHof = -277.7 kJ/mol

We can calculate ΔHrxn using ΔHof values. Look up the ΔHof values for each substance in the chemical equation. Sum the product standard enthalpies of formation, multiplying each value by the equation coefficient for that substance. Then sum the reactant standard enthalpies of formation, multiplying each value by the equation coefficient for that substance. Subtract the values for the reactants from the products:

ΔHorxn = ∑ m ΔHof (products) – ∑ n ΔHof (reactants)

The values of m and n are the coefficients of the products and reactants. For example, let’s calculate ΔHorxn for the following reaction:

2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)

Go to the table to look up the ΔHof values for each reactant and product.

ΔHof [O2 (g)] = 0 kJ/mol
ΔHof [C4H10 (g)] = -126 kJ/mol
ΔHof [CO2 (g)] = -393.5 kJ/mol
ΔHof [H2O (g)] = -241.8 kJ/mol

Recall, we subtract the reactants from the products and multiply each ΔHof value by the coefficient in the balanced chemical equation.

\(\displaystyle \Delta H_{rxn}\;=\;\Bigl [8\;mol\;CO_2\times\;-393.5\frac{kJ}{mol}\;+\;10\;mol\;H_2O\times\;-241.8\frac{kJ}{mol}\Bigr]\)


\(\displaystyle \Bigl [2\;mol\;C_4H_{10}\times\;-126\frac{kJ}{mol}\;+\;13\;mol\;O_2\times\;0\frac{kJ}{mol} \Bigr]\)

\(\displaystyle \;=\;\mathbf{-5314\;J}\)

For the combustion of two moles of butane, there is 5314 J of heat released. For the combustion of one mole of butane, divide equation coefficients and ΔHorxn by 2, there would be 2657 J of heat released.

Worksheet: Heats of Formation at 25 ℃

Exercises

Exercise 1. Write a formation reaction for K2CrO4 (s).

Exercise 2. What is the value of ΔHof for LiOH (s)? Write a formation equation for LiOH (s).

Exercise 3. Calculate ΔHorxn, in kJ for the following reaction. (Table of Thermodynamic Quantities)

Fe2O3 (s) + 3 CO (g) → 2 Fe (s) + 3 CO2 (g)

Exercise 4. Methylcyclopentane, C6H12, undergoes combustion according to the following equation:

C6H12 (l) + 9 O2 (g) → 6 CO2 (g) + 6 H2O (g)    ΔHorxn = -3672 kJ/mol

Use the standard heat of reaction, ΔHorxn, and the ΔHof values from the Table of Thermodynamic Quantities to calculate the standard enthalpy of formation, ΔHof for methylcyclopentane.

Check Solutions/Answers to Exercises

 
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